عسوله
New Member
السلام عليكم
ادري اني كثرة الطلبات بس مالي بعد الله الا انتم الله يرضى عليكم
ابي حل هذه الاسئله لانمي بجد محتاجه لها
الفزعه تكفون
ابي حل الي تعرفونه لو سؤال واحد ان شاءالله تكون المرة الاخيره الي بتعبكم معي
Question 1:
A parallel-plate capacitor with circular shaped plates, with a diameter of 4 cm and air-gap separation of 0.50 mm is connected to a 12 V battery, and fully charged. The battery is then disconnected, what is the charge on the capacitor?
Question 2:
Consider a charged parallel-plate capacitor. Which combination of changes would quadruple its capacitance and show how?
If you knew that the dielectric constant of glass is 7.6 and of polystyrene is 2.5, find the percentage error in your experiment.
Question 6:
A parallel-plate capacitor has rectangular plates of area 57 cm2 (length=19 cm and width=3 cm). The region between the plates is filled with a dielectric slab of dielectric constant K= 4 which can slide along the length of the capacitor. Initially, the slab completely fills the rectangular region, and the capacitor holds a charge of 0.1 µC. How far should the dielectric slab be pulled so that the stored energy is double its initial value?
ادري اني كثرة الطلبات بس مالي بعد الله الا انتم الله يرضى عليكم
ابي حل هذه الاسئله لانمي بجد محتاجه لها
الفزعه تكفون
ابي حل الي تعرفونه لو سؤال واحد ان شاءالله تكون المرة الاخيره الي بتعبكم معي
Question 1:
A parallel-plate capacitor with circular shaped plates, with a diameter of 4 cm and air-gap separation of 0.50 mm is connected to a 12 V battery, and fully charged. The battery is then disconnected, what is the charge on the capacitor?
Question 2:
Consider a charged parallel-plate capacitor. How can its capacitance be halved? Check all that apply from the list below and show how:
- Double the charge.
- Double the plate area.
- Double the plate separation.
- Halve the charge.
- Halve the plate area.
- Halve the plate separation.
Question 3:- Double the charge.
- Double the plate area.
- Double the plate separation.
- Halve the charge.
- Halve the plate area.
- Halve the plate separation.
Consider a charged parallel-plate capacitor. Which combination of changes would quadruple its capacitance and show how?
- Double the charge and double the plate area.
- Double the charge and double the plate separation.
- Halve the charge and double the plate separation.
- Halve the charge and double the plate area.
- Halve the plate separation and double the plate area.
- Double the plate separation and halve the plate area.
Question 4:- Double the charge and double the plate separation.
- Halve the charge and double the plate separation.
- Halve the charge and double the plate area.
- Halve the plate separation and double the plate area.
- Double the plate separation and halve the plate area.
[FONT='Times','serif']A parallel plate capacitor is formed from two square pieces of metal 0.040 m on a side. The plates are separated by 0.008 m, and the space between them is filled with insulating rubber, which has a dielectric constant of 6.7. When this capacitor is connected to a 25 volt battery, what is the magnitude of the charge on each plate?[/FONT]
Question 5:
If you knew that the dielectric constant of glass is 7.6 and of polystyrene is 2.5, find the percentage error in your experiment.
Question 6:
A parallel-plate capacitor has rectangular plates of area 57 cm2 (length=19 cm and width=3 cm). The region between the plates is filled with a dielectric slab of dielectric constant K= 4 which can slide along the length of the capacitor. Initially, the slab completely fills the rectangular region, and the capacitor holds a charge of 0.1 µC. How far should the dielectric slab be pulled so that the stored energy is double its initial value?
