Mohammeds1
New Member
I bought few grams of sodium sulfide hydrate (Na2S.xH2O + aq.) with a molecular weight of 78.04 + aq. and assay as (Na2S) of 55-58% as source of sulfur to prepare CdS nanoparticles. I am trying to follow similar previous protocol I found in literature where the authors used 1.4 mmol of Na2S.9H2O (99%) as a source of sulfur. I am little confused about preparing and measuring the accurate amount of Na2S.xH2O that I bought to match the exact amount of (1.4 mmol) of Na2S.9H2O used in previous investigation.
How can I know the exact x value in Na2S.xH2O
Should I dry the sodium sulfide hydrate and weigh as Na2S
Should I assume x = 3 with a M.W of 132.01 g/mol of Na2S.3H2O
Are there any differences between the two precursors that will effect the purity, morpholog, phase, size, rate of reaction...etc of the final product CdS
Is the assay as (Na2S) of 55-58% mean that there are impurties of 42% in the product
I am looking for your advice
Regards
How can I know the exact x value in Na2S.xH2O
Should I dry the sodium sulfide hydrate and weigh as Na2S
Should I assume x = 3 with a M.W of 132.01 g/mol of Na2S.3H2O
Are there any differences between the two precursors that will effect the purity, morpholog, phase, size, rate of reaction...etc of the final product CdS
Is the assay as (Na2S) of 55-58% mean that there are impurties of 42% in the product
I am looking for your advice
Regards